.. _pylab_examples-font_table_ttf: pylab_examples example code: font_table_ttf.py ============================================== [`source code `_] :: #!/usr/bin/env python # -*- noplot -*- """ matplotlib has support for freetype fonts. Here's a little example using the 'table' command to build a font table that shows the glyphs by character code. Usage python font_table_ttf.py somefile.ttf """ import sys import os import matplotlib from matplotlib.ft2font import FT2Font from matplotlib.font_manager import FontProperties from pylab import figure, table, show, axis, title import six from six import unichr # the font table grid labelc = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'] labelr = ['00', '10', '20', '30', '40', '50', '60', '70', '80', '90', 'A0', 'B0', 'C0', 'D0', 'E0', 'F0'] if len(sys.argv) > 1: fontname = sys.argv[1] else: fontname = os.path.join(matplotlib.get_data_path(), 'fonts', 'ttf', 'Vera.ttf') font = FT2Font(fontname) codes = list(font.get_charmap().items()) codes.sort() # a 16,16 array of character strings chars = [['' for c in range(16)] for r in range(16)] colors = [[(0.95, 0.95, 0.95) for c in range(16)] for r in range(16)] figure(figsize=(8, 4), dpi=120) for ccode, glyphind in codes: if ccode >= 256: continue r, c = divmod(ccode, 16) s = unichr(ccode) chars[r][c] = s lightgrn = (0.5, 0.8, 0.5) title(fontname) tab = table(cellText=chars, rowLabels=labelr, colLabels=labelc, rowColours=[lightgrn]*16, colColours=[lightgrn]*16, cellColours=colors, cellLoc='center', loc='upper left') for key, cell in tab.get_celld().items(): row, col = key if row > 0 and col > 0: cell.set_text_props(fontproperties=FontProperties(fname=fontname)) axis('off') show() Keywords: python, matplotlib, pylab, example, codex (see :ref:`how-to-search-examples`)